To a solution weighing 300 g with a mass fraction of sodium hydroxide 20 was added a solution containing an excess

| February 22, 2021 | education

To a solution weighing 300 g with a mass fraction of sodium hydroxide 20 was added a solution containing an excess of copper sulfate 2. Calculate the mass of the precipitate formed.

We draw up the reaction equation and determine the precipitate: 2NaOH + CuSO4 = Na2SO4 + Cu (OH) 2.
1) Find the mass of the sodium hydroxide solute in its solution. To do this, multiply the mass fraction of the substance by the mass of the solution and divide by one hundred percent: 300 * 20/100 = 60g.
2) Molar mass of sodium hydroxide: 23 + 1 + 16 = 40.
3) Amount of hydroxide substance: 60/40 = 1.5 mol.
4) According to the reaction equation, there is one mole of copper hydroxide for one mole of sodium hydroxide. This means that the amount of sediment substance is 1.5 mol.
5) Sludge weight: 1.5 * 98 = 147g – answer.



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