To a source with an EMF equal to 6V and an internal resistance of 1 ohm, 3 conductors connected in parallel

| May 5, 2021 | education

To a source with an EMF equal to 6V and an internal resistance of 1 ohm, 3 conductors connected in parallel are connected, and each with a resistance of 9 ohms. Find the amperage in the circuit.

Given:

U = 6 Volts – EMF of the power source;

r = 1 Ohm – internal resistance of the power supply;

R1 = R2 = R3 = 9 Ohm – resistances of the conductors connected to the power supply.

It is required to determine I (Ampere) – the current in the circuit.

Since, according to the condition of the problem, the conductors are connected in parallel, we find the total resistance of the conductors:

1 / R = 1 / R1 + 1 / R2 + 1 / R3;

1 / R = 1/9 + 1/9 + 1/9;

1 / R = 3/9 = 1/3;

R = 3 ohms.

Then the current strength will be equal to:

I = U / (r + R) = 6 / (1 + 3) = 6/4 = 1.5 Amperes.

Answer: the current in the circuit will be equal to 1.5 Amperes.



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