To an excess of potassium carbonate, 200 g of a solution with a mass fraction of sulfuric

| September 10, 2021 | education

To an excess of potassium carbonate, 200 g of a solution with a mass fraction of sulfuric acid of 5% was added, calculate the volume of the forming gas.

1. Find the mass of the solute (sulfuric acid) in the solution by the formula.

2. Let’s calculate the amount of sulfuric acid substance according to the formula n = m: M, where M is the molar mass. The molar mass of the acid is 98 g / mol (calculated using the periodic table).

3. We make the equation of the reaction between sulfuric acid and potassium carbonate. As a result, carbon dioxide is formed, the volume of which we need to find.

Using the reaction equation, we determine the quantitative ratios of acid and carbon dioxide. They react 1: 1 (1 mol of acid enters into the reaction and 1 mol of carbon dioxide is formed).

Then the amount of acid and gas will be the same, that is, n (CO2) = 0.1 mol.

4. Let’s calculate the volume of gas by the formula:

V = Vn n, where Vn is the molar volume equal to 22.4 l / mol, and n is the amount of substance.

V = 0.1 mol x 22.4 L / mol = 2.24 L.

Answer: V = 2.24 liters.



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