To burn 160 g of sulfur, 56 liters of oxygen were taken. Calculate the mass of the sour gas generated.

Let’s write the reaction equation:

S + O2 = SO2.

Let’s find the amount of reactants:

v (S) = m (S) / M (S) = 160/32 = 5 (mol),

v (O2) = V / Vm = 56 / 22.4 = 2.5 (mol).

According to the reaction equation, 1 mole of S reacts with 1 mole of O2.

However, by condition, O2 is taken in a deficit (2.5 mol per 5 mol S).

Therefore, the calculation is carried out for O2: 2.5 mol SO2 is obtained from 2.5 mol of O2.

Then, v (SO2) = 2.5 (mol) and the mass of sulfur dioxide:

m (SO2) = v (SO2) * M (SO2) = 2.5 * 64 = 160 (g).