To burn 40 liters of a mixture of propane and methane, 270.4 liters of oxygen were consumed.

univerkov | December 30, 2020 | education

To burn 40 liters of a mixture of propane and methane, 270.4 liters of oxygen were consumed. Determine the volume fraction of methane in the mixture.

C3H8 + 5O2 = 3CO2 + 4H2O
CH4 + 2O2 = CO2 + 2H2O
total amount of oxygen 5 + 2 = 7
calculate the volume of oxygen for methane
270.4-7
x = – 2
x = 77.26 l
calculate the volume of methane
x l = 77.26 l
CH4 + 2O2 = CO2 + 2H2O
22.4 = 44.8L
x = 22.4 * 77.26 / 44.8 = 38.63l
f = 38.63 / 40 = 0.966 or 96.6%

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