To completely neutralize a solution containing 0.1 mol of sulfuric acid, NaOH of mass (g) is required.

First, we compose the reaction equation.
2NaOH + H2SO4 → Na2SO4 + 2H2O.
Further, according to the reaction equation, we find the amount of sodium hydroxide substance. We write down the solution.
X mol NaOH – 0.1 mol H2SO4.
2 mol NaOH – 1 mol Н2SO4.
Find the unknown value of x.
X = 2 × 0.1 ÷ 1 = 0.2 mol NaOH.
Next, we find the mass of sodium hydroxide. For this we use the following formula.
n = m / M.
Where n is the amount of substance.
m is the mass of the substance.
M is the molar mass of the substance.
M (NaOH) = 23 + 16 + 1 = 40 g / mol.
m = n × M = 0.2 mol × 40 g / mol = 8 g.
Answer: m (NaOH) = 8 g.