To determine the strength of the electric field, a test charge q = 4 μC is placed at a certain point.

To determine the strength of the electric field, a test charge q = 4 μC is placed at a certain point. From the side of the field, a force equal to 0.08N acts. What is the field strength for the specified point.

Given:
q = 4 mk cells = 4 * 10 ^ -6 = 0.000004
F = 0.08 N
Decision:
The field strength is:
E = F / q
E = 0.08 / 4 * 10 ^ -6
E = 20,000
Answer: the field strength is 20,000