To determine the temperature in the furnace, a steel bolt weighing 0.3 kg heated in it was thrown into a copper

| March 26, 2021 | education

To determine the temperature in the furnace, a steel bolt weighing 0.3 kg heated in it was thrown into a copper vessel weighing 0.2 kg containing 1.2 kg of water at 15 degrees C. The temperature of the water rose to 32 degrees C. Calculate the furnace temperature.

Data: m1 (bolt mass) = 0.3 kg; m2 (vessel mass) = 0.2 kg; m3 (mass of water) = 1.2 kg; t1 (initial temperature of the vessel and water) = 15 ºС; tу (steady-state temperature) = 32 С.

Constants: C1 (heat capacity of steel) = 500 J / (kg * K); C2 (heat capacity of copper) = 400 J / (kg * K); C3 (heat capacity of water) = 4200 J / (kg * K).

Solution: C1 * m1 * (t2 – tу) = (С2 * m2 + C3 * m3) * (tу – t1).

t2 = (C2 * m2 + C3 * m3) * (tу – t1) / (C1 * m1) + t2.

t2 = (400 * 0.2 + 4200 * 1.2) * (32 – 15) / (500 * 0.3) + 32 = 612.27 ºС.



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