To experimentally determine the speed of sound, the student stood at a distance of 30 m from the wall

To experimentally determine the speed of sound, the student stood at a distance of 30 m from the wall and clapped his hands. At the moment of the clap, an electronic stopwatch turned on, which turned off with a reflected sound. The time indicated by the second measure is 0.18 s. What is the speed of sound? your decision is not correct. there, the time must be divided by two, since in 0.18 s the sound passed twice: against the walls and back.

Given:

L = 30 meters – distance from the wall to the student;

t = 0.18 seconds – the time interval after which the electronic stopwatch turned off from the sound reflected from the wall.

It is required to determine v (m / s) – the speed of sound.

The sound from the student’s clap went to the wall and then bounced off it and headed back towards the student. It turns out that the total distance traveled by the sound is equal to:

S = 2 * L = 2 * 30 = 60 meters.

Then, the speed of sound will be:

v = S / t = 60 / 0.18 = 333.3 m / s.

Answer: The speed of sound is 333.3 meters per second.