To fill the pool, first, one pipe was opened and after 2 hours, without closing it, the second was opened

To fill the pool, first, one pipe was opened and after 2 hours, without closing it, the second was opened. After 4 hours of joint operation of the pipes, the pool was filled. One second pipe could fill the pool 1.5 times faster than the first one. How many hours does it take to fill a pool through each pipe?

Let’s take the volume of water coming from the first pipe per hour for x liters. Then 1.5x liters are supplied from the second pipe in one hour.

We calculate the conditional value of the volume of water required to fill the pool We proceed from the fact that the first pipe was open for 2 + 4 = 6 hours, and the second only for 4 hours:

x * 6 + 1.5x * 4 = 6x + 6x = 12x liters of water.

If 1.5x liters per hour flows through the second pipe, then it will fill the pool in:

12x: 1.5x = 8 hours.

The pool will be filled through the first pipe for:

12x: x = 12 hours, which is 1.5 times slower than after the second.



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