To heat 2 kg of bronze by 20 degrees, 7600 J of heat is spent. What is the specific heat capacity of bronze?

Given:
m = 2kg
T2-T1 = 20 ° C
Q = 7600 J
from-? J \ kg
Decision:
Q = c * m * (T2-T1)
c = Q / (m * (T2-T1))
c = 7600J / (2kg * 20 ° C)
s = 190J / kg
Answer: 190J / kg



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