To heat a brick at t1 = 60 C, we spent the same amount of heat as for heating water (c2 = 4.2 J / kg * K)

To heat a brick at t1 = 60 C, we spent the same amount of heat as for heating water (c2 = 4.2 J / kg * K) with a mass of m2 = 2 kg at t2 = 26.4 C. If the mass of a brick is m1 = 4 kg, then its specific the heat capacity c1 is?

The amount of heat required to heat a body by Δt degrees is determined from the formula:
Q = m * c * Δt,
Where
m – body weight,
c – specific heat capacity of the substance,
Δt is the temperature difference;
For bricks:
Q1 = m1 * c1 * Δt1;
For water:
Q2 = m2 * c2 * Δt2;
m1 = 4kg,
m2 = 2kg,
c1 = 4200J / (kg * deg),
Δt1 = 60 ° С,
Δt2 = 26.4 ° С,
Q1 = Q2;
We get:
m1 * c1 * Δt1 = m2 * c2 * Δt2;
c1 = (m2 * c2 * Δt2) / (m1 * Δt1);
c1 = (2 * 4200 * 26.4) / (4 * 60) = 924J / (kg * deg).