To heat a brick weighing 4 kg from 15 ° C to 30 ° C, 48 kJ of heat was consumed. Find the specific heat of the brick.

Given: m (the mass of the brick taken) = 4 kg; t0 (initial brick temperature) = 15 ºС; t (final temperature) = 30 ºС; Q (consumed heat) = 48 kJ or 48 * 10 ^ 3 J.

To find the desired heat capacity of a brick, we use the formula: Q = CK * m * (t – t0), whence CK = Q / (m * (t – t0)).

Calculation: CK = 48 * 10 ^ 3 / (4 * (30 – 15)) = 48 * 10 ^ 3/60 = 800 J / (kg * K).

Answer: Brick, according to the calculation, has a specific heat equal to 800 J / (kg * K).