To heat a brick weighing 4 kg from 15 degrees to 30 degrees, 43 kJ of heat was consumed.
| June 16, 2021 | education
To heat a brick weighing 4 kg from 15 degrees to 30 degrees, 43 kJ of heat was consumed. Find the specific heat of the brick.
m = 4 kg.
t1 = 15 ° C.
t2 = 30 ° C.
Q = 43 kJ = 43000 J.
C -?
Q = C * m * (t2 – t1).
C = Q / m * (t2 – t1).
С = 43000 J / 4 kg * (30 ° C – 15 ° C) = 716 J / kg * ° C.
Answer: the specific heat of a brick is C = 716 J / kg * ° C.
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