To heat a concrete slab weighing 200 kg from 10 to 40 degrees, it took 5.3 * 10 ^ 6 J

To heat a concrete slab weighing 200 kg from 10 to 40 degrees, it took 5.3 * 10 ^ 6 J. of heat. Find the specific heat of concrete?

Problem data: m (mass of a heated concrete slab) = 200 kg; t0 (initial temperature of the slab) = 10 ºС; t (final temperature) = 40 ºС; Q (heat spent on heating the plate) = 5.3 * 10 ^ 6 J.

To determine the specific heat capacity of concrete, we will use the formula: Q = Cb * m * (t – t0), whence Cb = Q / (m * (t – t0)).

Let’s perform the calculation: Sat = 5.3 * 10 ^ 6 / (200 * (40 – 10)) = 883.3 J / (kg * K).

Answer: The specific heat capacity of concrete, according to the calculation, is equal to 883.3 J / (kg * K).