To heat a lead weight from 30 degrees Celsius to 50 degrees Celsius, it took the same amount of heat

To heat a lead weight from 30 degrees Celsius to 50 degrees Celsius, it took the same amount of heat as to heat 2 kg of water to 90 grams. Celsius. What is the mass of a lead weight?

T1 = 30;
t2 = 50;
c1 = 126J / kggrad;
It is also known that: Q1 = Q2.
m2 = 2kg;
Δt = 90;
c2 = 4200 J / kggrad;
Find m1;
Let’s write the formula:
Q1 = m1 * c1 (t2 – t1);
Q2 = m2 * c2 * Δt.
Let’s transform the formula for solving the problem:
m1 * c1 * (t2 – t1) = m2 * c2 * Δt.
m1 = 300 kg.
Answer: m1 = 300 kg.