To heat a maple bar weighing 4 kg from 15 to 30 degrees, 48 kJ of heat was consumed. Find the specific heat of maple.

We can find the specific heat “c” from the formula for finding the amount of heat Q = cm (t2-t1). Whence c = Q / m * (t2-t1)
Convert 48kJ to J 48000J
Let’s substitute in the formula the values, 48000/4 * (30-15) = 800J or 0.8 kJ



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