To heat a metal with a mass of 50g from a temperature of 20c to a temperature of 21c, an amount of heat equal to 230 J

To heat a metal with a mass of 50g from a temperature of 20c to a temperature of 21c, an amount of heat equal to 230 J was required. Determine the specific heat of the metal.

Given:
m = 50 g = 0.05 kg
t1 = 20 degrees Celsius
t2 = 21 degrees Celsius
Q = 230 J
Find: with -?
Decision:
Q = c * m * (t2-t1)
c = Q / m * (t2-t1)
c = 230 / 0.05 * (21-20) = 230 / 0.05 = 4600 J / kg * degree Celsius
Answer: 4600 J / kg * degree Celsius