To heat the lead part to 10 degrees, 1400 J of heat was spent, what is the mass of the part.

univerkov | May 15, 2021 | education

These tasks: Δt (change in the temperature of the lead part during heating) = 10 ºС; Q (consumed thermal energy) = 1400 J.

Reference values: Cc (specific heat of lead) = 140 J / (kg * K).

The mass of the lead part taken can be expressed from the formula: Q = Cc * m * Δt, whence m = Q / (Cc * Δt).

Let’s perform the calculation: m = 1400 / (140 * 10) = 1 kg.

Answer: The taken lead part has a mass of 1 kilogram.

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