To move a body weighing 8000 N to a height of 1 m, an inclined plane with a length of 4 m was used while moving along

To move a body weighing 8000 N to a height of 1 m, an inclined plane with a length of 4 m was used while moving along an inclined plane, a friction force of 1000 N was applied to the body. What is the efficiency?

Let’s calculate the body weight by the formula: m = P / g where P is the body weight, g is the acceleration of gravity:
m = 8000/10 = 800 kg.
The change in the potential energy of the body is equal to: ΔW = mgh, where h is the height.
ΔW = 800 * 10 * 1 = 8000 J.
Let’s define the work of the friction force, A = F * S where F is the force, S is the distance.
A = 1000 * 4 = 4000 J
Then the total energy change is:
8000 + 4000 = 12000 J.
Efficiency = 8000/12000 = 2/3 = 67%.