To move a cabinet weighing 120 kg on the floor, a horizontal force of 600n should be offered

To move a cabinet weighing 120 kg on the floor, a horizontal force of 600n should be offered to it. Find the coefficient of friction between carpet and floor?

Initial data: F (horizontal force required to move the cabinet) = 600 N, m (cabinet weight) = 120 kg.

Constants: g (acceleration due to gravity) = 10 m / s ^ 2.

Since the horizontal force is completely spent on overcoming the frictional force between the carpet and the floor, the following relationship is true:

F = Ftr. = μ * m * g.

μ = F / (m * g).

Let’s perform the calculation:

μ = 600 / (120 * 10) = 0.5.

Answer: The coefficient of friction between carpet and floor is 0.5.