To neutralize 20.5 g of calcium hydroxide, 560 ml of nitric acid solution (density 1.51 g / ml)

To neutralize 20.5 g of calcium hydroxide, 560 ml of nitric acid solution (density 1.51 g / ml) were used. Calculate the mass fraction of nitric acid in the solution.

We draw up an equation for the ongoing reaction and place the coefficients:
Ca (OH) 2 + 2HNO3 = Ca (NO3) 2 + 2H2O.
1) Find the mass of nitric acid. To do this, multiply the volume of acid by its density: 560 * 1.51 = 845.6 g.
2) The mass of the entire solution will be the sum of the mass of calcium hydroxide and the mass of nitric acid: 845.6 + 20.5 = 866.1 g.
3) Find the mass fraction of nitric acid in the solution. To do this, divide the mass of nitric acid by the mass of the solution and multiply by one hundred percent: 845.6 / 866.1 * 100 = 97.6% – the answer.



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