To neutralize 200 g of a solution with a mass fraction of acetic acid of 9%, sodium hydroxide with a mass of?

univerkov | April 9, 2021 | education

CH3COOH + NaOH = CH3COONa + H2O.
1) Find the mass of the acetic acid solute in its solution. To do this, we multiply the mass fraction of the substance by the mass of the solution and divide by one hundred percent: 200 * 9/100 = 18g.
2) According to the periodic table, we find the molar mass of acetic acid: 12 + 3 + 12 + 16 + 16 + 1 = 60.
3) Amount of acetic acid substance: 18/60 = 0.3 mol.
4) According to the reaction equation, one mole of acetic acid accounts for one mole of sodium hydroxide. This means that the amount of hydroxide substance is 0.3 mol.
5) The mass of sodium hydroxide is: 0.3 * 40 = 12g – the answer.

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