To neutralize a solution containing 16 g of sodium hydroxide, a solution of hydrochloric acid with a mass

| September 16, 2021 | education

To neutralize a solution containing 16 g of sodium hydroxide, a solution of hydrochloric acid with a mass fraction of a substance of 15% was spent calculate the mass of the spent acid solution

Find the amount of NaOH.

n = m: M.

M (NaOH) = 40 g / mol.

n = 16 g: 40 g / mol = 0.4 mol.

Let’s find the quantitative ratios of substances.

NaOH + HCl = NaCl + H2O.

1 mol of NaOH accounts for 1 mol of HCl.

Substances are in quantitative ratios 1: 1.

The amount of substance will be equal.

n (NaOH) = n (HCl) = 0.4 mol.

Find the mass of HCl.

m = n × M.

M (HCl) = 36.5 g / mol.

m = 36.5 g / mol × 0.4 mol = 14.6 g.

Find the mass of sulfuric acid in the solution.

W = m (substance): m (solution) × 100%,

hence m (solution) = m (substance): w) × 100%.

m (solution) = (14.6: 15) × 100% = 97.33 g.

Answer: 97.33 g.



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