To neutralize table vinegar, it took 200 g of a 30% sodium hydroxide solution.

| February 6, 2021 | education

To neutralize table vinegar, it took 200 g of a 30% sodium hydroxide solution. Calculate the mass and amount of the acetic acid substance that has reacted.

CH3COOH + NaOH = CH3COONa + H2O
Let’s calculate the mass of sodium hydroxide that has reacted:
m (NaOH) = m solution * w (NaOH) = 200 * 0.3 = 60 g.
Next, we calculate the amount of sodium hydroxide substance that has reacted:
n (NaOH) = m (NaOH) / M (NaOH) = 60/40 = 1.5 mol
where the molar mass of sodium hydroxide is calculated as follows:
M (NaOH) = 23 + 16 +1 = 40 g / mol
It follows from the reaction equation that for alkali and acid react in equal amounts, that is
n (NaOH) = n (CH3COOH) = 1.5 mol
and calculate the mass of acetic acid that has reacted:
m (CH3COOH) = n (CH3COOH) * M (CH3COOH) = 1.5 * 48 = 72 g.
Where the molar mass of acetic acid is calculated as follows:
M (CH3COOH) = 12 + 3 * 1 + 16 + 16 + 1 = 48 g / mol
Answer: 1.5 mol and 72 g.



One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.