To obtain 260 kg of aniline, 250 kg of benzene were consumed. Calculate the aniline yield (in%) of theoretical.

given:
m (c6h5no2) = 74.4 g
to find:
m (c6h6) =?
decision:
c6h6 + hno3 = c6h5no2 + h2o
n (c6h5no2) = m / M = 74.4 / 93.13 = 0.8 mol
0.8 / 1 = x / 1 hence x = 0.8 mol
m (c6h6) = n * M = 0.8 * 78.11 = 62.488 g
answer: m (c6h6) = 62.488 g



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