To obtain 44.8 liters of carbon dioxide, you need calcium carbonate in mass?

1. We write down the reaction equation for the decomposition of calcium carbonate:

CaCO3 = CaO + CO2 ↑;

2.Calculate the chemical amount of carbon dioxide produced:

n (CO2) = V (CO2): Vm = 44.8: 22.4 = 2 mol;

3.According to the recording of the ongoing reaction, the amounts of gas and carbonate will coincide:

n (CaCO3) = n (CO2) = 2 mol;

4. calculate the mass of the required carbonate:

m (CaCO3) = n (CaCO3) * M (CaCO3);

M (CaCO3) = 40 + 12 + 3 * 16 = 100 g / mol;

m (CaCO3) = 2 * 100 = 200 g.

Answer: 200 g.