To obtain ammonia, 32.1 g of ammonium chloride and an excess of calcium hydroxide were taken

To obtain ammonia, 32.1 g of ammonium chloride and an excess of calcium hydroxide were taken in the laboratory. calculate the amount of ammonia that can be obtained by this?

The reaction of ammonium chloride with calcium hydroxide is described by the following chemical reaction equation:

2NH4Cl + Ca (OH) 2 = 2NH3 + CaCl2 + 2H2O;

Two moles of ammonium chloride react with one mole of calcium hydroxide.

Determine the amount of substance in 32.1 grams of ammonium chloride.

M NH4Cl = 14 + 4 + 35.5 = 53.5 grams / mol;

N NH4Cl = 32.1 / 53.5 = 0.6 mol;

M Ca (OH) 2 = 40 + 16 x 2 + 2 = 74 grams / mol;

N Ca (OH) 2 = 20/74 = 0.27 mol;

0.6 mol of ammonium chloride will react with 0.3 mol of calcium hydroxide to form 0.6 mol of ammonia.

Let’s find its mass and volume:

Under normal conditions, one mole of ideal gas takes up a volume of 22.4 liters.

V NH3 = 0.6 x 22.4 = 13.44 liters;