To obtain ammonia, 6 liters of nitrogen and 6 liters of hydrogen were mixed. What substance will be consumed completely

To obtain ammonia, 6 liters of nitrogen and 6 liters of hydrogen were mixed. What substance will be consumed completely, what will remain in excess and how much?

The reaction of obtaining ammonia:
N2 + 3H2 = 2NH3.
Let’s find the number of moles of starting substances:
n (N2) = 6 / 22.4 = 0.268 mol.
n (H2) = 6 / 22.4 = 0.268 mol.
Calculation of the amount of mol of ammonia in nitrogen:
n (NH3) = 0.268 * 2 = 0.536 mol.
Hydrogen calculation:
n (NH3) = 0.268 * 2/3 = 0.179 mol.
Remaining mole of nitrogen:
n (N2) = 0.268 – 0.179 = 0.089 mol.
Accordingly, out of 6 liters of nitrogen (excess) will remain:
V (N2) = 0.089 * 22.4 = 1.994 liters.
This means that there will be nitrogen in excess, and hydrogen will completely react.