# To obtain cuprum (||) oxide with a mass of 2.4, copper with a mass of 1.92 was heated in acids, write down

**To obtain cuprum (||) oxide with a mass of 2.4, copper with a mass of 1.92 was heated in acids, write down the reaction levels and determine the type of reaction and the mass of heated oxygen.**

Copper reacts with oxygen to form oxide. The reaction is described by the following chemical reaction equation:

Cu + ½ O2 = CuO ↑;

Let’s find the chemical amount of copper. For this purpose, we divide the weight of the available substance by the weight of 1 mole.

M Cu = 64 grams / mol;

N Cu = 1.92 / 64 = 0.03 mol;

To oxidize such an amount of copper, it is necessary to take 2 times less oxygen.

Let’s calculate the weight and volume of oxygen.

To find the weight, we multiply the amount of the substance by the weight of 1 mole of the substance.

M O2 = 16 x 2 = 32 grams / mol;

m O2 = 0.03 / 2 x 32 = 0.48 grams;

To find the volume of oxygen, we multiply the amount of the substance by the volume of 1 mole of gas (which is 22.4 liters).

m O2 = 0.03 / 2 x 22.4 = 0.336 liters;