To prepare a dilute solution of hydrochloric acid, 0.3 l was added to 200 g of a 25% solution

To prepare a dilute solution of hydrochloric acid, 0.3 l was added to 200 g of a 25% solution. What is the mass fraction of HCl in the resulting solution?

given
hydrochloric acid solution = 200 grams
solution = 25 percent
added 0.3 liters
find the mass fraction of HCl, or in another way its percentage solution
decision
first we find the mass that was originally, that is, in the first solution and we get
mass of substance = mass of solution * percentage of solution = 200 grams * 25 percent = 200 grams * 25 percent / 100 percent = 200 * 25/100 grams = 200 * 25 / (25 * 4) grams = 200 * 1 / (1 * 4 ) grams = 200/4 grams = 50 grams
now we will find the percentage of solution in the resulting solution
ω ₂ = 500 grams / (200 grams + 0.3 liters) = 50 grams / (200 grams + 300 grams) = 50 / (200 + 300) = 50/500 = 50 / (10 * 50) = 1/10 or 10 percent
answer: 10 percent



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