To rinse a copper piece weighing 17.8 kg, it was lowered into a tank with kerosene.

To rinse a copper piece weighing 17.8 kg, it was lowered into a tank with kerosene. Determine the mass of kerosene displaced by this part.

1) Calculate the volume of the copper part:

V = m1 / ρ1, where m1 is the mass of the copper part (m1 = 17.8 kg), ρ1 is the density of copper (ρ1 = 8900 kg / m3).

V = m1 / ρ1 = 17.8 / 8900 = 0.002 m3.

2) Since the volume of the body will be equal to the volume of the displaced kerosene, the volume of the displaced kerosene is 0.002 m3.

3) Let’s calculate the mass of the displaced kerosene:

m2 = V * ρ2, where ρ2 is the density of kerosene (ρ2 = 800 kg / m3).

m2 = V * ρ2 = 0.002 * 800 = 1.6 kg.

Answer: The mass of kerosene displaced by the part is 1.6 kg.