To rinse the steel part, it was lowered into a tank of kerosene. The volume of kerosene displaced
| April 18, 2021 | education
To rinse the steel part, it was lowered into a tank of kerosene. The volume of kerosene displaced by this part is 0.8 dm3. Determine the mass of the part.
Given:
V = 0.8 cubic decimeters = 0.0008 cubic meters – the volume of kerosene displaced by the steel part;
ro = 7800 kilograms per cubic meter – the density of steel.
It is required to determine m (kilogram) – the mass of the steel part.
According to Archimedes’ law, the volume of fluid displaced by a body during full immersion is equal to the volume of the body. This means that the volume of the steel part is V = 0.0008 cubic meters. Then the mass of the part is equal to:
m = ro * V = 7800 * 0.0008 = 6.24 kilograms.
Answer: The mass of the steel part is 6.24 kilograms.
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