To stretch an undeformed spring by 5 cm, a force of 15 N is required. What is the cruelty of the spring?

Given:

dx = 5 centimeters = 0.05 meters – the amount by which the undeformed spring was stretched;

F = 15 Newton – the force applied to stretch the spring.

It is required to determine k (Newton / meter) – coefficient of spring stiffness.

To determine the coefficient of spring stiffness, you need to use the following formula (Hooke’s law):

F = dx * k, hence:

k = F / dx = 15 / 0.05 = 300 Newton / meter.

Answer: The coefficient of spring stiffness is 300 Newton / meter.