To the potassium carbonate solution was added 45 grams of a 15% hydrochloric acid solution.
To the potassium carbonate solution was added 45 grams of a 15% hydrochloric acid solution. Calculate the volume of carbon dioxide.
We compose the reaction equation and arrange the coefficients:
K2CO3 + 2HCl = 2KCl + H2O + CO2.
1) Find the mass of the solute of hydrochloric acid. To do this, we multiply the mass fraction of the substance by the mass of the solution and divide by one hundred percent: 45 * 15/100 = 6.75 g.
2) Find the molar mass of hydrochloric acid according to the periodic table: 1 + 35.5 = 36.5.
3) Find the amount of hydrochloric acid substance: 6.75 / 36.5 = 0.18 mol.
4) According to the reaction equation, there is one mole of carbon dioxide per mole of hydrochloric acid. This means that the amount of carbon dioxide substance is 0.18 mol.
5) The volume of carbon dioxide is: 0.18 * 22.4 = 4.032 liters – the answer.