To wash a copper part weighing 17.8 kg, it was lowered into a tank with kerosene.
| March 11, 2021 | education
To wash a copper part weighing 17.8 kg, it was lowered into a tank with kerosene. Determine the mass of kerosene displaced by this part.
mm = 17.8 kg.
ρm = 8900 kg / m ^ 3.
ρк = 800 kg / m ^ 3.
mk -?
The volume of displaced kerosene Vk is equal to the volume of the submerged part Vm: Vk = Vm.
Vk = mk / ρk.
Vm = mm / ρm.
mk / ρk = mm / ρm.
mk = mm * ρk / ρm.
mk = 17.8 kg * 800 kg / m ^ 3/8900 kg / m ^ 3 = 1.6 m ^ 3.
Answer: mk = 1.6 m ^ 3.
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