To what height can a body weighing 2 kg be lifted by performing a work of 0.6 kJ?

m = 2 kg.

g = 10 N / kg.

A = 0.6 kJ = 600 J.

h -?

We will assume that the lifting of the body is carried out by a vertical force F and uniformly.

The work of force A is determined by the formula: A = F * S * cosα, where S is the movement of the body, ∠α is the angle between the force F and the movement of the body S.

Since a vertical force acts on the body and it moves vertically upwards, then ∠α = 0 °, cos0 ° = 1, S = h.

According to 1 Newton’s law, the force F with which the body is lifted is equal to the gravity of the body m * g: F = m * g.

A = m * g * h.

h = A / m * g.

h = 600 J / 2 kg * 10 N / kg = 30 m.

Answer: the body can be raised to a height of h = 30 m.

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