To what height does the arrow rise if it is fired from a crossbow at a speed of 60 m / s.

1) Traveled path:

S = (V ^ 2 – V0 ^ 2) / 2a, V is the speed of the arrow at the maximum height (V = 0 m / s), V0 is the speed of the arrow at the time of the shot from the crossbow (V0 = 60 m / s), and – the movement is equally slow (a = -g = 10 m / s2).

S = V0 ^ 2 / 2g.

2) According to the law of conservation of energy (the kinetic energy of the arrow will go into potential):

Ek = En.

m * V ^ 2/2 = m * g * h.

V ^ 2/2 = g * h and h = V ^ 2 / 2g.

Let’s make a calculation:

S = h = 60 ^ 2 / (2 * 10) = 3600/20 = 180 m.

Answer: The arrow will rise to a height of 180 meters.