To what height from the initial position could a car weighing 1000 kg rise on the road going

To what height from the initial position could a car weighing 1000 kg rise on the road going uphill, if all the heat of combustion when burning 10 kg of gasoline in the engine was spent only to increase its potential energy? Specific heat of combustion of gasoline 44 10 ^ 6 J kg

ma = 1000 kg.
g = 9.8 m / s ^ 2.
mbenz = 10 kg.
λ = 44 * 10 ^ 6 J / kg.
h -?
When gasoline is burned, the amount of heat Q is obtained, which is determined by the formula: Q = λ * mbenz, where λ is the specific heat of combustion of gasoline, mbenz is the mass of gasoline that burned.
All this amount of thermal energy Q will be converted into the potential energy of the vehicle Еп: Q = Еп.
The values ​​of which are determined by the formula: En = ma * g * h, where ma is the mass of the car, g is the acceleration of gravity, h is the height of the car above the ground.
λ * mbenz = ma * g * h.
h = λ * mbenz / ma * g.
h = 44 * 10 ^ 6 J / kg * 10 kg / 1000 kg * 9.8 m / s ^ 2 = 44897 m.
Answer: the car would rise to a height of h = 44897 m.