To what rate can you heat 500 g of water, giving it 84 kJ of heat? Initial water temperature 20 ℃

These tasks: m (mass of heated water) = 500 g (in SI m = 0.5 kg); Q (heat imparted to water) = 84 kJ (84 * 10 ^ 3 J); t0 (temperature before heat transfer) = 20 ºС.

Reference values: Sv (specific heat of water) = 4200 J / (kg * K).

The temperature to which the taken water will be heated can be expressed from the formula: Q = Cw * m * (t – t0) and t = Q / (Cw * m) + t0.

Calculation: t = 84 * 10 ^ 3 / (4200 * 0.5) + 20 = 40 + 20 = 60 ºС.

Answer: The taken water can be heated up to 60 ºС.



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