To what speed can a car accelerate in 3 seconds if the coefficient of friction between the tires

To what speed can a car accelerate in 3 seconds if the coefficient of friction between the tires and the horizontal road is 0.5?

A car of mass m moves along a horizontal road, which means that the resultant of horizontal forces according to Newton’s second law will be determined by the formula: F = m ∙ a, where a is acceleration.
Acceleration is determined by the initial speed v₀, the final speed v and the acceleration time t of the car according to the formula: a = (v – v₀) / t. Since the car accelerates, then its initial speed is v₀ = 0 m / s, then: a = v / t. We get: F = m ∙ v / t.
The car is affected by the friction force Ffr = μ ∙ m ∙ g, where μ is the coefficient of friction between the tires and the road, and the coefficient g ≈ 9.8 m / s ^ 2. The traction force is spent on acceleration and overcoming the friction force, then m ∙ v / t = μ ∙ m ∙ g or
v = μ ∙ g ∙ t.
Since the time t = 3s, the friction coefficient μ = 0.5, then
v = 0.5 ∙ 9.8 m / s ^ 2 ∙ 3 ​​s ≈ 15 m / s.
Answer: the car can accelerate up to a speed of ≈ 15 m / s.