To what temperature will 100 grams of lead be heated if the initial temperature is 18 degrees, and 600 kJ was spent?

univerkov | February 22, 2021 | education

Data: m (mass of taken lead) = 100 g (0.1 kg); t0 (temperature before heat transfer) = 18 ºС; Q (heat for heating) = 600 kJ (600 * 10 ^ 3 J).

Constants: Сс (specific heat capacity of lead) = 140 J / (kg * K).

We express the temperature that lead will reach from the formula: Q = Cc * m * (t – t0), whence t = Q / (Cc * m) + t0.

Calculation: t = 600 * 103 / (140 * 0.1) + 18 = 42 875 ºС; lead will reach a melting point of 327.4 ºС and completely melt.

Answer: Lead will heat up to a temperature of 327.4 ºС.

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