Took a solution of CuSO4 weighing 100 g with a mass fraction of salt of 6%. To this solution was added NaOH

Took a solution of CuSO4 weighing 100 g with a mass fraction of salt of 6%. To this solution was added NaOH weighing 1.2 g. Determine the mass of the sediment formed.

CuSO4 + 2NaOH = Cu (OH) 2 + Na2SO4.
1) Find the mass of the solute of copper sulfate. To do this, we multiply the mass fraction of the substance by the mass of the solution and divide by one hundred percent: 100 * 6/100 = 6g.
2) Molar mass of copper sulfate: 64 + 32 + 64 = 160.
3) The amount of copper sulfate substance: 6/160 = 0.04 mol.
4) Molar mass of sodium hydroxide: 23 + 1 + 16 = 40.
5) The amount of sodium hydroxide substance: 1.2 / 40 = 0.03 mol.
Lack of sodium hydroxide. The calculation is carried out on it.
6) Sludge weight: 0.03 * 98 = 2.94 g – answer.