Triangle ABC Angle A is 90 degrees, Angle B is 30 degrees, side AB is 6 cm. Find the sides of the triangle.

We write down the definition of the tangent of angle B specifically for our condition, use the tabular value of the tangent of 30 ° and find the AC leg:
Tg B = AC / AB → AC = tan 30 ° * AB = √3 / 3 * 6 = 2√3 (cm).
The found leg AC is located opposite the angle B, the degree measure of which is 30 °. From this it follows that it is equal to half of the hypotenuse of the BC, and the hypotenuse itself is equal to:
BC = 2 * AC = 2 * 2√3 = 4√3 (cm).
Answer: 2√3 cm and 4√3 cm.