Triangle ABC, angle C 50 degrees, angle A 20 degrees greater than angle B. Find angle A angle B.

By the theorem on the sum of the angles of a triangle:
angle A + angle B + angle C = 180 degrees.
Let the angle B = x, then the angle A = x + 20 (since the angle A is 20 degrees greater than the angle B – by condition). Then:
x + 20 + x + 50 = 180;
2x = 180 – 70;
2x = 110;
x = 110/2;
x = 55 degrees.
Angle A = x + 20 = 55 + 20 = 75 (degrees), angle B = x = 55 degrees.
Answer: angle A = 75 degrees, angle B = 55 degrees.