Triangle ABC, angle C = 90 degrees. AC = 2, AB = 2√3. Find angle B?

The tangent of an acute angle of a right-angled triangle is equal to the ratio of the opposite leg to the adjacent leg.

tgABC = AC / BC = 2/2 * √3 = 1 / √3 = √3 / 3.

Angle ABC = arctan (√3 / 3) = 30.



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