Triangle ABC, angle C = 90 degrees AC = 6 cm BC = 8 cm Find: Tangent of angle B, Sine of angle A

Both legs of a right-angled triangle are known, we write down the tangent of angle B by definition and find it:
Tg B = AC / BC = 6/8 = 3/4 = 0.75.
We find the hypotenuse AB:
AB = √ (AC² + BC²) = (36 + 64) = √100 = 10 (cm).
Find the sine of angle A by definition:
Sin A = BC / AB = 8/10 = 0.8.
Answer: tg B = 0.75, sin A = 0.8.



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