Triangle ABC, angle C is 90 degrees, angle A is 10 degrees greater than angle B, find angles AB.

Let x be angle B, then angle A-x + 10;
The acute angles of a right-angled triangle add up to 90 degrees;
Let’s make the equation:
x + x + 10 = 90;
2x + 10 = 90;
2x = 90-10;
2x = 80;
x = 40;
Since angle B is x, so angle A is angle B + 10;
Angle A = 40 + 10 = 50;
We check:
40 + 50 = 90; 50 is more than 40 by 10 degrees