Triangle ABC is inscribed in a circle centered at point O. Find the angle ACB if the angle AOB is 73 degrees.

The central angle inscribed in the circle of the triangle is equal to the arc on which it rests => angle AOB = arc AB The inscribed angle is equal to half of the arc on which it rests => ACB = 1/2 of arc AB Based on this, we can conclude that the inscribed angle equal to half of the central angle resting on the same arc ACB = 1 / 2AOB = 36.5.

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