Triangle ABC is isosceles, angle ABC is 20 degrees. line EF is drawn through vertex B
| September 7, 2021 | education
Triangle ABC is isosceles, angle ABC is 20 degrees. line EF is drawn through vertex B of this triangle, parallel to line AC. Find: angle ABE.
Since the triangle ABC is isosceles, the angle BAC = BCA = (180 – ABC) / 2 = (180 – 20) / 2 = 80.
According to the condition, the straight line EF is parallel to AC, then the angle ABE = BAC = 80 as criss-crossing angles at the intersection of parallel straight lines AC and EF secant AB.
Answer: Angle ABE is 80.
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